Looking through my list of friends recently on my favorite social media platform, I noticed that people tended to fall into a small number of “sets.” That is, if you I knew you through work, I probably did not grow up with you, and if you fell into one of these two groups, I probably didn’t go to college with you.
However, looking at the characteristics of people’s first names, it was easy to construct multiple criteria that multiple had in common. For example, both “David” and “Penny” have not only 5 letters in their names, but also have a repeated letter, where “Debra” and “Adam” meet one or the other criteria, but not both, and “Mike” meets neither.
Each given criteria can split your list of friends into two groups: those that meet the criteria, and those that don’t. Given four criteria, you can split a list of people into some 16 groups.
Below is a list of 4 criteria, and 47 different names. The four criteria individually each split the group exactly in half, and, when applied together, split the list into equal groups — almost.
This week’s Geekdad Puzzle of the Week: Which of the 16 groups defined by these 4 criteria only has two members (and not three like the rest)?
Criteria #1: An odd number of letters in their name.
Criteria #2: Their name sums to a prime (A=1, B=2,.. Z=26, so ADAM=19, etc.)
Criteria #3: Duplicates a letter (like DAVID or SCOTT.)
Criteria #4: Has an even number of vowels (A,E,I,O, and U only.)
List of names:
ADAM ALLISON AMBER ANGELA ASTRID BETSY BRITTANY CANDACE CARMELO CATHERINE CHIQUITA CHRISTIAN |
CLAUDIA DAMON DAVID DWIGHT ELEANOR HENRY HUNTER JACKSON JACQUELINE JULIET KATE LAUREN |
LILY LOUISA MANDI MATT MAX MICHELLE MILLICENT NORA OCTAVIA PENNY PORTIA RILEY |
ROBERT SABINE SCARLETT SCOTT SHAWN TOBIAS TODD VICTORIA WANDA WENDY WILFRED |
Given the list above, ADAM is one of the three names that fails Criteria #1, but meets #2, #3, and #4.
As always, please send your response into GeekDad Central. The winner of this week’s fabulous prize, a $50 Gift Certificate from our friends at ThinkGeek, will be determined by a random drawing from among the correct (or at least reasonably well-reasoned) entries.
Good luck, and happy puzzling!